Thread Rating:
  • 0 Vote(s) - 0 Average
  • 1
  • 2
  • 3
  • 4
  • 5
Calulating higher derivatives
#1
I don't really think this would count as homework help because we havn't exactly gotten to this in class. I just briefly saw it in Essential Calculus: Early Transcendentals that there are derivatives of higher orders.

Would I be correct in assuming that a derivative of the next order is just a derivative of a derivative? As in lets say that f(x) = x^4.

Using the power rule, the derivative would be:

f'(x) = 4x^3

The derivative of the next order would be:

f''(x) = 12x^2

Going along with this pattern:

f'''(x) = 24x
Reply
#2
That's right. f^(n) (x) denotes higher derivatives when the nth derivative gets large.
[Image: Anvil.png]THIS COMMENT PROUDLY FORGED BY LOADED ANVILS[Image: Anvil.png]
Reply


Forum Jump:


Users browsing this thread: 1 Guest(s)